[Boatanchors] 6BE6 VFO/Mixer Tube

[jmfranke]

In the Drake 2B, pin 6 of the 6BE6 - the screen - is the anode for the 
Hartley oscillator formed with G1 (pin 1), and the cathode (pin 2).  RF is 
inserted via G2 (pin 7).  The product of the two signals appears at the 
anode (pin 5).  There is no direct oscillator output per say.  The 
oscillator modulates the electrons coming from the cathode.  To check the 
oscillator portion of the circuit for V3, V4, or V7, check the cathode  (pin 
2).

John  WA4WDL

--------------------------------------------------
From: "Lee Buller" <k0wa at swbell.net>
Sent: Thursday, December 03, 2009 4:02 PM
To: <boatanchors at mailman.qth.net>
Subject: [Boatanchors] 6BE6 VFO/Mixer Tube

>
>
> I am trying to figure out how the 6BE6 works with a VFO and a mixer in the 
> same tube.
>
> 1. Where is the output of the VFO or oscillator?
> 2. isn't the output of the plate of the 6BE6 the sum or minus of the two 
> signals coming in? The one from the previous amplifier and the VFO?
> 3. Where would you pick off RF or use a counter probe to see what the VFO 
> is doing?
>
> It seems the 6BE6 was being used like this in a score of old receivers. I 
> get the tube is using feeback through the cathode...but I just don't get 
> the output of the VFO? Where is that? For instance...the Drake 2B.
>
> Lee - K0WA
>
>
> In our day and age it seems that Common Sense is in short supply.  If you 
> don't have any Common Sense - get some Common Sense and use it.  If you 
> can't find any Common Sense, ask for help from somebody who has some 
> Common Sense.  Is Common Sense divine?
>
> Common Sense is the image of the Creator expressing revealed truth in my 
> mind. - J. Wolf
>
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